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ScienceQuest
Biology Practice Undergraduate

Lab and Clinical Calculation Practice Problems

Practise the calculations labs and clinics run, from doubling time and centrifuge force to QTc, MAP and the A-a gradient, each one marked instantly.

Practice

Question 1 of 40

Cell Doubling Time Calculator

Starting count
N₀ = 97,000 cells
Elapsed time
t = 49 h
Doubling time
Td = 7 h
cells

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Worked answers

The first ten questions from the set above, each with its answer and the working that gets there. The working is carried out in the units each equation takes, so its last line can show the answer before it is converted.

  1. Starting count
    N₀ = 97,000 cells
    Elapsed time
    t = 49 h
    Doubling time
    Td = 7 h

    Find the final count (N).

    Show the answer and working

    Answer N = 1.242 × 10⁷ cells

    Rearranged N = N₀ × 2^(t / Td)

    1. N = N0 x 2^(t / Td)
    2. = 97,000 x 2^(49 / 7)
    3. = 97,000 x 2^7
    4. = 1.2416 × 10⁷ cells

    Check it with the Cell Doubling Time Calculator.

  2. Relative centrifugal force
    RCF = 32,000 × g
    Rotor speed
    RPM = 22,000 rpm

    Find the rotor radius (r).

    Show the answer and working

    Answer r = 5.912 cm

    Rearranged r = RCF ÷ (1.11824 × 10⁻⁵ · RPM²)

    1. r = RCF / (1.11824 × 10⁻⁵ x RPM^2)
    2. = 32,000 / (1.11824 × 10⁻⁵ x 4.84 × 10⁸)
    3. = 32,000 / 5412.3
    4. = 5.912 cm

    Check it with the Centrifuge RCF Calculator.

  3. Absorbance at 260 nm
    A₂₆₀ = 0.15 AU
    Extinction factor
    ε = 47 µg/mL
    Dilution factor
    d = 22×

    Find the concentration (c).

    Show the answer and working

    Answer c = 155.1 ng/µL

    Rearranged c = A₂₆₀ × ε × d

    1. c = A260 x factor x dilution
    2. = 0.15 x 47 x 22
    3. = 155.1 ng/uL

    Check it with the Nucleic Acid Quantification Calculator.

  4. Systolic pressure
    SBP = 180 mmHg
    Mean arterial pressure
    MAP = 120 mmHg

    Find the diastolic pressure (DBP).

    Show the answer and working

    Answer DBP = 90 mmHg

    Rearranged DBP = (3 · MAP - SBP) ÷ 2

    1. DBP = (3 MAP - SBP) / 2
    2. = (3 x 120 - 180) / 2
    3. = 180 / 2
    4. = 90 mmHg

    Check it with the Mean Arterial Pressure Calculator.

  5. Serum albumin
    alb = 2.7 g/dL
    Corrected calcium
    Ca corr = 12 mg/dL

    Find the measured total calcium (Ca).

    Show the answer and working

    Answer Ca = 10.96 mg/dL

    Rearranged Ca = Ca corr - 0.8 × (4.0 - alb)

    1. Ca measured = Ca corrected - 0.8 x (4.0 - albumin)
    2. = 12 - 0.8 x (4.0 - 2.7)
    3. = 12 - 1.04
    4. = 10.96 mg/dL

    Check it with the Albumin Corrected Calcium Calculator.

  6. Inspired oxygen
    FiO2 = 48 %
    Arterial CO2
    PaCO2 = 75 mmHg
    Arterial O2
    PaO2 = 210 mmHg
    Barometric pressure
    Patm = 680 mmHg
    A-a gradient
    16 mmHg

    Find the respiratory quotient (R).

    Show the answer and working

    Answer R = 0.9635

    Rearranged R = PaCO2 ÷ [FiO2 · (Patm - 47) - PaO2 - (A-a)]

    1. R = PaCO2 / [FiO2 x (Patm - PH2O) - PaO2 - (A-a)]
    2. = 75 / [303.84 - 210 - 16]
    3. = 75 / 77.84
    4. = 0.9635

    Check it with the A-a Gradient and Alveolar Gas Equation Calculator.

  7. Heart rate
    HR = 62 bpm
    Corrected QT, Bazett
    QTc = 430 ms

    Find the measured QT.

    Show the answer and working

    Answer QT = 423 ms

    Rearranged QT = QTc × √RR

    1. RR = 60 / HR
    2. = 60 / 62 = 0.9677 s
    3. QT = QTc x sqrt(RR)
    4. = 430 x 0.9837
    5. = 423 ms

    Check it with the QTc Calculator.

  8. Final count
    N = 1.6 × 10⁶ cells
    Elapsed time
    t = 74 h
    Doubling time
    Td = 28 h

    Find the starting count (N₀).

    Show the answer and working

    Answer N₀ = 256,200 cells

    Rearranged N₀ = N ÷ 2^(t / Td)

    1. N0 = N / 2^(t / Td)
    2. = 1.6 × 10⁶ / 2^(74 / 28)
    3. = 1.6 × 10⁶ / 2^2.643
    4. = 256,180 cells

    Check it with the Cell Doubling Time Calculator.

  9. Rotor speed
    RPM = 21,000 rpm
    Rotor radius
    r = 29 cm

    Find the relative centrifugal force (RCF).

    Show the answer and working

    Answer RCF = 143,000 × g

    Rearranged RCF = 1.11824 × 10⁻⁵ · r(cm) · RPM²

    1. RCF = 1.11824 × 10⁻⁵ x r(cm) x RPM^2
    2. r = 29 cm
    3. = 1.11824 × 10⁻⁵ x 29 x 21,000^2
    4. = 1.11824 × 10⁻⁵ x 29 x 4.41 × 10⁸
    5. = 143,010 x g

    Check it with the Centrifuge RCF Calculator.

  10. Serum albumin
    alb = 4.2 g/dL
    Corrected calcium
    Ca corr = 10 mg/dL

    Find the measured total calcium (Ca).

    Show the answer and working

    Answer Ca = 10.16 mg/dL

    Rearranged Ca = Ca corr - 0.8 × (4.0 - alb)

    1. Ca measured = Ca corrected - 0.8 x (4.0 - albumin)
    2. = 10 - 0.8 x (4.0 - 4.2)
    3. = 10 + 0.16
    4. = 10.16 mg/dL

    Check it with the Albumin Corrected Calcium Calculator.

The calculators behind the questions

Every question is generated from one of these 10 calculators, and links back to the one it came from: A-a Gradient and Alveolar Gas Equation Calculator, Albumin Corrected Calcium Calculator, Body Surface Area Calculator, Cell Doubling Time Calculator, Centrifuge RCF Calculator, Ligation Calculator, Mean Arterial Pressure Calculator, Nucleic Acid Quantification Calculator, QTc Calculator and Serum Osmolality and Osmolar Gap Calculator.

Write down the assumption, not just the numbers

Each lab calculation here turns a proxy into the thing you want, and each proxy holds only while its assumption does. Absorbance stands in for mass of nucleic acid, which needs the right extinction factor. Rotor speed stands in for the force on a pellet, which needs the rotor radius. Two counts stand in for a growth rate, which needs exponential growth between them. The formula returns a plausible figure whether or not the assumption held. The clinical questions rest on assumptions of their own: a QTc depends on which correction formula was applied, and an A-a gradient on the barometric pressure given to the alveolar gas equation.

So write the assumption beside the numbers, put both times in the same unit, and take the rotor radius from the rotor’s documentation rather than the length of the tube.

Where lab calculations go wrong

  • A spin quoted in RPM. Speed is not force. 13,000 rpm in a rotor of 8.5 cm radius is about 16,000 × g, and the same speed in a larger rotor delivers more. A protocol in RPM is reproducible only on the centrifuge it was written on.
  • The wrong extinction factor. An absorbance of 1.0 over a 1 cm path is 50 µg/mL for double-stranded DNA, 40 for RNA and 33 for single-stranded DNA. Applying 50 to an RNA sample overstates the concentration by 25 percent, and nothing flags it. Keep the reading between 0.1 and 1.0, where the instrument is linear.
  • The dilution factor dropped. An A260 of 0.15 read on a 1 in 10 dilution is 0.15 × 50 × 10 = 75 ng/µL. Without the factor it is 7.5, and both are concentrations a real prep might have.
  • Counts that straddle the wrong phase. A doubling time is defined for exponential growth. Two counts spanning a lag phase, or a culture that has hit confluence, return a figure that overstates the true doubling time.

Checking a result you cannot repeat

Use the exponents. Relative centrifugal force goes as the square of the speed, so a 10 percent error in RPM is a 21 percent error in force, while it is only linear in radius. Concentration from absorbance is linear in all three inputs, which makes an answer out by exactly ten a dilution factor.

Doubling times have an exact check whenever the counts are related by a power of two. Going from 100,000 to 800,000 is three doublings however long it took, so 48 hours of that growth is a 16 hour doubling time, no logarithms required. Then compare against what is normal: E. coli in rich medium manages about 20 minutes, yeast about 90 minutes and HeLa cells roughly 24 hours.

Units that look different and are not

One pair is identical and often treated as though it were not: 1 ng/µL is exactly 1 µg/mL. Relative centrifugal force is the other quiet one, a dimensionless multiple of 9.80665 m/s² rather than a force in newtons, which is why it is written × g.

Mass and molar amount are not interchangeable, and the conversion depends on length. A base pair of double-stranded DNA averages about 650 g/mol, so a 1 kb fragment is around 650,000 g/mol and 1 µg of it is roughly 1.5 pmol. Molecule count scales inversely with length, so 100 ng of a 200 bp fragment holds about 50 times as many molecules as 100 ng of a 10 kb fragment.

Common questions

Where do these questions and answers come from?

Every question is generated from the specification behind one of the lab or clinical calculators on this site. The values you are given are drawn at random around each calculator’s own default figures, and the answer is computed by the same solver the calculator uses, so the two can never disagree. That also means the assumptions built into a calculator, such as the extinction factor or the rotor radius, are the assumptions built into the question.

Is my progress saved?

No. There is no account and nothing is stored, so no score carries over from a previous visit, and a page reload resets the count and starts you at a random point in the same set of questions. While you stay on the page you get a running count of how many you have answered correctly out of how many you have attempted, and that count is the only record kept.